Design a diode clipper that limits the output to between -0.7V and +5.7V for a sine wave input of (\pm 10V).

Vin = 10V R1 = 1kΩ R2 = 2kΩ D1 = Silicon Diode D2 = Silicon Diode

[ r_d = \fracnV_TI_D = \frac1 \times 25mV1mA = 25\Omega ] The AC output voltage is found by treating (r_d) as a resistor in a voltage divider.

[Answer Box] Vdc≈9.9V, PIV≥17V, fripple=120Hz

Diodes clamp voltage across load to ±0.7V. So load voltage is a clipped sine wave at ±0.7V.